rising-crimson•2y ago

Question no setFilter

Hi I am new to refine. One of my projects require a dropdown to filter results from table. I find that by setting the filter to an empty array won't clear all the filter, instead I need to set the value in the filter to undefined ,is it a correct way to do? e.g. setFilter([]) not work

setFilter(
[{
  "field": "location_id",
  "operator": "in",
  "value": undefined,
}]
)

setFilter(
[{
  "field": "location_id",
  "operator": "in",
  "value": undefined,
}]
)

this works

2 Replies

kapa.ai•2y ago

Hi @samwalker. I'm kapa.ai, your friendly support bot. I will try to answer your question by searching through the knowledge base. :wave: ---------------------- Yes, you are correct. In refine, when you are using the setFilters function with merge behavior (which is the default behavior), to remove a specific filter, you should set the value to undefined or null. If you want to remove or filters, you should set the value to an empty array []. Here is the relevant part from the documentation:

Merge behavior: If you are using merge behavior and want to remove one of the filters, you should set the value to undefined or null. For or filters, you should set the value to an empty array [] to remove the filter.

So, your approach is correct. Here is how you can do it:

setFilters(
  [{
    "field": "location_id",
    "operator": "in",
    "value": undefined,
  }]
)

setFilters(
  [{
    "field": "location_id",
    "operator": "in",
    "value": undefined,
  }]
)

This will effectively remove the filter for the location_id field. For more information, you can refer to the useTable documentation (https://refine.dev/docs/data/hooks/use-table#filtering). ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------

kapa.ai•2y ago

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Question no setFilter

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