optimistic-gold
optimistic-gold2mo ago

selectProps

is it possible to concat the optionLabel in selectProps so onselect show for example two diferent labels like "name" and "code": const { selectProps: selectPropsClients}, } = useSelect({ resource: "clients", pagination: { mode: "off", }, optionLabel: "name", optionValue: "id", });
22 Replies
kapa.ai
kapa.ai2mo ago
Hi @Sly. I'm kapa.ai, your friendly support bot. I will try to answer your question by searching through the knowledge base. :wave: ---------------------- Yes, it is possible to concatenate two different labels in the optionLabel of selectProps. You can achieve this by passing a function to optionLabel that returns the concatenated string. Here is an example:
const { selectProps: selectPropsClients } = useSelect({
resource: "clients",
pagination: {
mode: "off",
},
optionLabel: (item) => `${item.name} ${item.code}`,
optionValue: "id",
});
const { selectProps: selectPropsClients } = useSelect({
resource: "clients",
pagination: {
mode: "off",
},
optionLabel: (item) => `${item.name} ${item.code}`,
optionValue: "id",
});
In this example, item is each individual option object. The function takes this object and returns a string that concatenates the name and code properties of the object. This approach was suggested in a Github issue (https://github.com/refinedev/refine/issues/4880) discussion for the refine project. ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
kapa.ai
kapa.ai2mo ago
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optimistic-gold
optimistic-gold2mo ago
@kapa.ai Im getting this error: Type '(item: any) => string' is not assignable to type '"id"'
kapa.ai
kapa.ai2mo ago
Let me check the knowledge base for you. One moment! :books: ---------------------- It seems like TypeScript is expecting the optionLabel to be of type "id", but you're providing a function instead. This could be due to a type definition in your project that is not allowing a function for optionLabel. Unfortunately, the provided knowledge sources do not contain a direct solution to this issue. However, you might want to check your type definitions and ensure that a function is allowed for optionLabel. If you're still having trouble, I would recommend checking the Refine documentation (https://refine.dev/docs/api-reference/hooks/form/useSelect) or seeking help from the Refine community (https://discord.com/channels/837692625737613362/1183789260407591065). ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
kapa.ai
kapa.ai2mo ago
<@1172098337760096258> kapa.ai is still learning and improving, please let us know how it did by reacting below
optimistic-gold
optimistic-gold2mo ago
@kapa.ai when i use this "optionLabel: (item) => ${item.name} ${item.code}, " I get this error "Type '(item: any) => string' is not assignable to type '"id"'"
kapa.ai
kapa.ai2mo ago
Let me check the knowledge base for you. One moment! :books: ---------------------- The error you're encountering is due to TypeScript expecting the optionLabel to be of type "id", but you're providing a function instead. This could be due to a type definition in your project that is not allowing a function for optionLabel. However, according to a Github issue (https://github.com/refinedev/refine/issues/4880) discussion, it should be possible to use a function for optionLabel in useSelect. Here's the suggested usage:
useSelect({
optionLabel: (item) => `${item.someField} ${item.anotherField}`,
optionValue: (item) => item.foo.id,
})
useSelect({
optionLabel: (item) => `${item.someField} ${item.anotherField}`,
optionValue: (item) => item.foo.id,
})
If you're still having trouble, it might be due to the version of Refine you're using. The feature to use a function for optionLabel might not be available in the version you're using. You might need to update your version of Refine to the latest one. If updating Refine doesn't solve the issue, I would recommend checking the Refine documentation (https://refine.dev/docs/api-reference/hooks/form/useSelect) or seeking help from the Refine community (https://discord.com/channels/837692625737613362/1183789260407591065). ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
kapa.ai
kapa.ai2mo ago
<@1172098337760096258> kapa.ai is still learning and improving, please let us know how it did by reacting below
optimistic-gold
optimistic-gold2mo ago
@kapa.ai how to update refine?
kapa.ai
kapa.ai2mo ago
Let me check the knowledge base for you. One moment! :books: ---------------------- You can update your Refine packages using the Refine CLI. First, you need to check for updates. You can do this by running the following command:
npm run refine check-updates
npm run refine check-updates
This command will show you the running versions of the installed Refine packages and if there are any updates available. If there are updates available, you can update your Refine packages to the wanted version by running the following command:
npm run refine update
npm run refine update
This information is based on the Refine CLI documentation (https://refine.dev/docs/packages/cli#check-updates). ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
kapa.ai
kapa.ai2mo ago
<@1172098337760096258> kapa.ai is still learning and improving, please let us know how it did by reacting below
optimistic-gold
optimistic-gold2mo ago
@kapa.ai filters are not working when using optionLabel: (item) => ${item.someField} ${item.anotherField},
kapa.ai
kapa.ai2mo ago
Let me check the knowledge base for you. One moment! :books: ---------------------- The issue you're experiencing might be due to the way filters are handled when using a function for optionLabel. When you use a function for optionLabel, the filtering might not work as expected because the filter might be trying to match the filter value with the concatenated string. Unfortunately, the provided knowledge sources do not contain a direct solution to this issue. However, you might want to check your filter logic and ensure that it can handle the concatenated string. If you're still having trouble, I would recommend checking the Refine documentation (https://refine.dev/docs/api-reference/hooks/form/useSelect) or seeking help from the Refine community (https://discord.com/channels/837692625737613362/1183789260407591065). ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
kapa.ai
kapa.ai2mo ago
<@1172098337760096258> kapa.ai is still learning and improving, please let us know how it did by reacting below
optimistic-gold
optimistic-gold2mo ago
@kapa.ai how to handle the concatenated string: const { selectProps: selectPropsClients }, } = useSelect({ resource: "clients", pagination: { mode: "off", }, optionLabel: (item: { name: any; branch: any; }) => ${item.name} ${item.branch}, optionValue: "id", });
kapa.ai
kapa.ai2mo ago
Let me check the knowledge base for you. One moment! :books: ---------------------- To handle the concatenated string in the optionLabel, you can use the queryOptions prop of useSelect to modify the data before it's used. Here's an example:
const { selectProps: selectPropsClients } = useSelect({
resource: "clients",
pagination: {
mode: "off",
},
optionLabel: "fullName",
optionValue: "id",
queryOptions: {
select: (data) => {
return {
data: data?.data?.map((item: any) => ({
...item,
fullName: `${item.name} ${item.branch}`,
})),
total: data.total,
};
},
},
});
const { selectProps: selectPropsClients } = useSelect({
resource: "clients",
pagination: {
mode: "off",
},
optionLabel: "fullName",
optionValue: "id",
queryOptions: {
select: (data) => {
return {
data: data?.data?.map((item: any) => ({
...item,
fullName: `${item.name} ${item.branch}`,
})),
total: data.total,
};
},
},
});
In this example, the select function in queryOptions is used to modify the data before it's used. It maps over the data and adds a new fullName property to each item, which is the concatenation of the name and branch properties. Then, fullName is used as the optionLabel. This approach was suggested in a Discord support thread (https://discord.com/channels/837692625737613362/1211786058891665449) for the refine project. ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
optimistic-gold
optimistic-gold2mo ago
@kapa.ai still not filtering... : GET http://192.168.0.35:1340/api/clients?&filters[fullName][$containsi]=ased 400 (Bad Request)
kapa.ai
kapa.ai2mo ago
Let me check the knowledge base for you. One moment! :books: ---------------------- The error message indicates that the server is not able to handle the filter request. The filter is trying to filter on the fullName field, which is a concatenated string of name and branch that you created on the client side. However, the server doesn't recognize this fullName field because it doesn't exist in the server's data model. To resolve this issue, you need to implement the filtering logic on the server side to handle the fullName field. This would involve modifying your server's API to accept a fullName filter and split it into name and branch for filtering. Unfortunately, the provided knowledge sources do not contain specific instructions on how to implement this server-side logic. You might need to refer to the documentation of your server-side technology or seek help from relevant communities. If you're using Refine's data provider, you might want to check the Refine documentation on handling filters in a data provider (https://refine.dev/docs/advanced-tutorials/data-provider/handling-filters/#handle-filters-in-a-data-provider) for some guidance. ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
kapa.ai
kapa.ai2mo ago
<@1172098337760096258> kapa.ai is still learning and improving, please let us know how it did by reacting below
optimistic-gold
optimistic-gold2mo ago
@kapa.ai how to show only the active data on selectProps
kapa.ai
kapa.ai2mo ago
Let me check the knowledge base for you. One moment! :books: ---------------------- To show only the active data in selectProps, you can use the filters prop of useSelect. You can pass a filter to the getList method from the dataProvider as a parameter via the useList hook. This filter will be used to send filter query parameters to the API. Here's an example:
const { selectProps: selectPropsClients } = useSelect({
resource: "clients",
filters: [
{
field: "isActive",
operator: "eq",
value: true,
},
],
});
const { selectProps: selectPropsClients } = useSelect({
resource: "clients",
filters: [
{
field: "isActive",
operator: "eq",
value: true,
},
],
});
In this example, the filters prop is used to filter the options you are showing. The field is "isActive", the operator is "eq" (equals), and the value is true. This means it will only show the clients where isActive is true. This approach is described in the Refine documentation on useSelect (https://refine.dev/docs/ui-integrations/ant-design/hooks/use-select#filters). ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
kapa.ai
kapa.ai2mo ago
<@1172098337760096258> kapa.ai is still learning and improving, please let us know how it did by reacting below