refine edit template "back"

button won't work
5 Replies
kapa.ai
kapa.ai2mo ago
Hi @koop_g. I'm kapa.ai, your friendly support bot. I will try to answer your question by searching through the knowledge base. :wave: ---------------------- Based on the knowledge sources provided, it seems there might be an issue with the "back" button functionality in the refine edit template. Let's explore the possible reasons and solutions: 1. Route parameter issue: If your route doesn't have an :action parameter or your action is list, the back button might not be shown even if you pass a goBack property. You can override this behavior by using the headerProps property. Here's an example of how to fix this:
import { useBack } from "@refinedev/core";
import { Edit } from "@refinedev/antd";
import { Button } from "antd";

const PostEdit: React.FC = () => {
const back = useBack();
const BackButton = () => <Button>←</Button>;

return (
<Edit goBack={<BackButton />} headerProps={{ onBack: back }}>
<p>Rest of your page here</p>
</Edit>
);
};
import { useBack } from "@refinedev/core";
import { Edit } from "@refinedev/antd";
import { Button } from "antd";

const PostEdit: React.FC = () => {
const back = useBack();
const BackButton = () => <Button>←</Button>;

return (
<Edit goBack={<BackButton />} headerProps={{ onBack: back }}>
<p>Rest of your page here</p>
</Edit>
);
};
This solution is mentioned in the Ant Design Edit Component documentation. 2. Version-specific behavior: If you're using an older version of refine (e.g., v3), there might be a difference in how the goBack prop works. In older versions, goBack only changed the icon, not the entire button functionality. To resolve this, you can either: a) Upgrade to the latest version of refine b) Use event.stopPropagation and event.preventDefault in your onClick callback if you want to change the go back functionality. 3. Using useBack hook: If you want to implement a custom back button, you can use the useBack hook from refine. Here's an example:
import { useBack } from "@refinedev/core";

const MyComponent = () => {
const back = useBack();

return <Button onClick={() => back()}>Go Back</Button>;
};
import { useBack } from "@refinedev/core";

const MyComponent = () => {
const back = useBack();

return <Button onClick={() => back()}>Go Back</Button>;
};
This approach is documented in the useBack hook documentation. If none of these solutions work for your specific case, it might be helpful to check your refine version and provide more details about your implementation. The issue could be related to your specific setup or configuration. ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
kapa.ai
kapa.ai2mo ago
<@1327562833537400895> Kapa.ai is still learning and improving, please let me know how I did by reacting below.
conscious-sapphire
conscious-sapphireOP2mo ago
@kapa.ai can I force back to take me to show page ?
kapa.ai
kapa.ai2mo ago
Let me check the knowledge base for you again. One moment! :books: ---------------------- Yes, you can force the back button to take you to the show page in refine. There are a couple of ways to achieve this: 1. Using the redirect property: You can use the redirect property in the useForm hook to specify where you want to redirect after a form submission. Here's how you can set it to go to the show page:
import { useForm } from "@refinedev/core";

const { ... } = useForm({
redirect: "show",
});
import { useForm } from "@refinedev/core";

const { ... } = useForm({
redirect: "show",
});
This is documented in the useForm hook documentation. 2. Using the redirect function: If you need more control over the redirection, you can use the redirect function returned by the useForm hook. This allows you to programmatically specify the destination:
const {
refineCore: { onFinish, redirect },
} = useForm();

const handleSubmit = async (e: React.FormEvent<HTMLFormElement>) => {
e.preventDefault();
const data = await onFinish(formValues);
redirect("show", data?.data?.id);
};
const {
refineCore: { onFinish, redirect },
} = useForm();

const handleSubmit = async (e: React.FormEvent<HTMLFormElement>) => {
e.preventDefault();
const data = await onFinish(formValues);
redirect("show", data?.data?.id);
};
This approach is mentioned in the useForm return values documentation. 3. Using the useBack hook with custom logic: If you specifically want to modify the behavior of the back button, you can use the useBack hook and implement custom logic:
import { useBack, useResource } from "@refinedev/core";
import { Button } from "@your-ui-library";

const BackButton = () => {
const back = useBack();
const { id } = useResource();

const handleBack = () => {
// Redirect to the show page instead of the default back behavior
back(`/your-resource/show/${id}`);
};

return <Button onClick={handleBack}>Back to Show</Button>;
};
import { useBack, useResource } from "@refinedev/core";
import { Button } from "@your-ui-library";

const BackButton = () => {
const back = useBack();
const { id } = useResource();

const handleBack = () => {
// Redirect to the show page instead of the default back behavior
back(`/your-resource/show/${id}`);
};

return <Button onClick={handleBack}>Back to Show</Button>;
};
Then you can use this custom BackButton in your Edit component:
import { Edit } from "@refinedev/your-ui-package";
const YourEditComponent = () => {
return (
<Edit goBack={<BackButton />}>
{/* Your form fields */}
</Edit>
);
};
import { Edit } from "@refinedev/your-ui-package";
const YourEditComponent = () => {
return (
<Edit goBack={<BackButton />}>
{/* Your form fields */}
</Edit>
);
};
This approach combines the useBack hook documented here with custom logic to achieve the desired behavior. Remember to adjust the resource name and paths according to your specific setup. ---------------------- Note: you can ask me a follow up question by @ mentioning me again :speech_balloon: ----------------------
kapa.ai
kapa.ai2mo ago
<@1327562833537400895> Kapa.ai is still learning and improving, please let me know how I did by reacting below.

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